|
UNIQUE NUMBERS |
If a number An consisting of n consecutive digits in ascending order is subtracted from the number An' obtained by reversing the digits of An, then the difference is always a constant. This constant is termed as the Unique number Un as reported by me earlier in [1].
For example, a 3-digit number 345 if subtracted from its reverse 543, yields a difference of 198. Thus U3 = 198. Another 3-digit number, say, 678 if subtracted from its reverse 876 will also yield the same difference, that is, 198. Thus for any number consisting of 3 consecutive digits, the Unique number U3 is always 198. Similarly for a number consisting of 4 consecutive digits, the Unique number U4 = 3087. Given below is a table of Unique numbers from U2 to U10 (U1 = 0).
|
U2 |
= |
0 9 |
|
U3 |
= |
1 98 |
|
U4 |
= |
3 087 |
|
U5 |
= |
4 1976 |
|
U6 |
= |
5 30865 |
|
U7 |
= |
6 419754 |
|
U8 |
= |
7 5308643 |
|
U9 |
= |
8 64197532 |
|
U10 |
= |
9 753086421 |
A glance at the table will reveal the following fascinating characteristics of Unique numbers:
|
U2 U1 |
= |
09 |
|
U3 U2 |
= |
189 |
|
U4 U3 |
= |
2889 |
|
U5 U4 |
= |
38889 |
|
U6 U5 |
= |
488889 |
|
U7 U6 |
= |
5888889 |
|
U8 U7 |
= |
68888889 |
|
U9 U8 |
= |
788888889 |
|
U10 U9 |
= |
8888888889 |
It can be seen that the first digit of all numbers gradually increases from 0 to 8, the last digit is 9 and the remaining digits are 8.
All the above properties were reported earlier in [1].
Let Un' denote the number obtained from a Unique number Un by writing its decimal digits in reverse order. For example U3 = 198, so U3' = 891. The following interesting pattern is obtained by summing Un and Un'.
|
U3+ U3' |
= |
1 089 |
|
U4+ U4' |
= |
1 0890 |
|
U5+ U5' |
= |
1 09890 |
|
U6+ U6' |
= |
1 098900 |
|
U7+ U7' |
= |
1 0998900 |
|
U8+U8' |
= |
1 09989000 |
|
U9+ U9' |
= |
1 099989000 |
|
U10 + U10' |
= |
1 0999890000 |
Relation of Unique numbers with Kaprekar Constant:
If 4-digit Kaprekar constant is denoted by K4 i.e. 6174 and the reverse of K4 by K4' i.e. 4716 then it can be noted that U4+ U4' = K4+ K4' i.e.
|
3 087 + 7803 = 10890 = 6174 + 4716 |
Similarly for 3-digit Kaprekar constant, we get K3 = 495 and K3' = 594, So
It can be noted that U3+ U3' = K3+ K3' i.e.
|
1 98 + 891 = 1089 = 495 + 594 |
----------------------------------------------------------------------------------------
[1] Unique Numbers, S. S. Gupta, Science Today, January 1988, India.
Back Home